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Mathematics 19 Online
OpenStudy (anonymous):

can someone check my calculus work

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

i can confused about #2

myininaya (myininaya):

i cant read this real well but it looks like there might have been a mistake on the first question \[[(f(x))^2]'=2f(x)f'(x)\] did you do this or did you do: \[2f'(x)?\]

OpenStudy (anonymous):

looks like you wanted the equation for the tangent line, and all the work is right but i think your slope should be 1/3

OpenStudy (anonymous):

Here are the questions

OpenStudy (anonymous):

then whats the y-intercept?

myininaya (myininaya):

it looks like the very last two questions is right

myininaya (myininaya):

i will leave everything else to satellite

OpenStudy (anonymous):

for #2 you wrote \[\frac{4}{3\cdot 4}=\text{something}\] that i cannot quite read. but is should be \[\frac{1}{3}\] so that the slope of your line is \[\frac{1}{3}\]

OpenStudy (anonymous):

But that question is asking for the x and y intercepts

OpenStudy (anonymous):

then the equation for the line will be \[y-2=\frac{1}{3}(x-1)\] \[y=\frac{1}{3}x+\frac{5}{3}\]

OpenStudy (anonymous):

it is asking for the x any y intercepts of the tangent line right? they will be \[\frac{5}{3}\] and \[-5\]

OpenStudy (anonymous):

shouldn't the x-intercept be 6/3 which is 2 because 1/3+ 5/3=6/3

OpenStudy (anonymous):

oops y-intercept should equal 2, and the x-intercept should equal 1

OpenStudy (anonymous):

x intercept of \[y=\frac{1}{3}x+\frac{5}{3}\] is what you get when you set \[y=0\] and solve for x it will be \[0=\frac{1}{3}x+\frac{5}{3}\] and so \[x=-5\]

OpenStudy (anonymous):

oh, I thought I had to plug in the points (1,2)

OpenStudy (anonymous):

again i think you made a mistake in finding the slope.

OpenStudy (anonymous):

you use the point (1,2) to find the equation of the line. it has slope 1/3 and goes through the point (1,2)

OpenStudy (anonymous):

but somewhere when you went to compute the slope you had all the numbers correct, but you should have \[\frac{4}{3\cdot 4}=\frac{1}{3}\] and it looks like you wrote something else

OpenStudy (anonymous):

no actually i see you did write 1/3 but now you need to use it to find the equation of the tangent line.

OpenStudy (anonymous):

I did write that made final answer after taking the derivative was 4/3(4x+4)^(2/3) and I just plug in 1 to solve for the slope which gave me 1/3

OpenStudy (anonymous):

whew

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

was all my others work right?

OpenStudy (anonymous):

but now you have to find the equation of the line through (1,2) with slope 1/3, and i think you skipped that part

OpenStudy (anonymous):

#10 is good we did that the other night i think

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

we did do it the other night

OpenStudy (anonymous):

the rest look good too, but if you really want to check post them one at a time, and let some other eyes look at them. some are hard for me to read

OpenStudy (anonymous):

ok thanks!

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