Question

rationalize the denominator of 7/(3 + √3)

Answer 1

Multiply top and bottom by 3-√3 to get


\[\Large \frac{7(3-\sqrt{3})}{(3+\sqrt{3})(3-\sqrt{3})}\]


\[\Large \frac{21-7\sqrt{3}}{3^2-(\sqrt{3})^2}\]


\[\Large \frac{21-7\sqrt{3}}{9-3}\]


\[\Large \frac{21-7\sqrt{3}}{6}\]


So \[\Large \frac{7}{3+\sqrt{3}} = \frac{21-7\sqrt{3}}{6}\]

Answer 2

21-7 square root 3/ 6..