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How do i integrate this by parts x^11sin(x^6)dx?
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\[\int x^{11}Sin(x^6)dx\]
?
U sub u= x^6 du = 6x^5
du* u= 6 x^11
\[\frac{1}{6}\int u Sin(u) du \]
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do integration by parts a = u db= sin(u) da= 1 du b= -Cos(u)
-u Cos(u)+ \[\int Cos(u) du\] \[\frac{1}{6}(-u Cos(u)+ Sin(u)+C)\]
u= x^6 thus put that back in \[\frac{1}{6}(-x^6 Cos(x^6)+ Sin(x^6)+C)\]
how did you get (1/6)?
du* u= 6 x^11 we want x^11 so we divide by 6
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