Sat.
\[\sqrt{9x+81}=x+5\]And \[9x+81 = (x+5)^2\] what's the difference?
? one is the square of the other
no, but try that in wolf. you willl get different answers.
that is because they are different
how?
well because if for example i know x = 5, then i know x^2=25 but if i know x^2=25 then i don't know that x = 5
because of course it could be x = -5
right, but the confusion is that in which one i get 2 answers?
so just because one square is equal to another, it doesn't mean you started with the same thing. when you square both sides of an equation you can introduce a solution that was not in the original equation
so in sqrt one, i get 2 solutions? right?
there are two solutions to \[9x+81=(x+5)^2\]
why not to the first one?
\[x=-8,x=7\] but only one solution to \[\sqrt{9x+81}=x+5\]
why not for the first one?
well you can see that \[x=-8\] does not work
Oh i seee. Now i get that... thanks man!
and you can even see why. if you replace x by -8 you get \[\sqrt{9}=-3\] i.e. \[3=-3\] which is false, but if you square both sides you get \[9=9\] which is true
THanks. one more question.
yw
what's the deal with: \[\Huge \sqrt[12]{(-9)^{12}}\]
when you raise to an even power it is positive, so you get 9 as your answer
\[\Huge \sqrt[13]{(-9)^{13}}\]Now?
-9"
?
yes
so the deal lies with even numbers....
if the exponent is even then you will get a positive number
ok, thanks. now can you please come and see the question just above this one? pixie's question.
ok, i think i just added a comment to that one
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