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Mathematics 10 Online
OpenStudy (anonymous):

need help with this differential equation. It will be in a picture in the next post.

OpenStudy (anonymous):

we've learned to about exact equations, using the x/y method, standard linear form (integrating factor), and separating the variables.

OpenStudy (anonymous):

I suspect I may have to manipulate this algebraically somehow then use x/y method but I don't know what to do.

OpenStudy (anonymous):

you picture is cut off

OpenStudy (anonymous):

It's actually a couple problems I need help with though. I can put the whole pdf if you wish.

OpenStudy (anonymous):

number three is what im doing now that should be there no?

OpenStudy (anonymous):

\[\frac{dy}{dx}=\frac{x+y}{y^3-2xy}\] \[-(x+y)dx+(y^3-2xy )dy=\] Let's see if it is exact ? let's check mix partial nope!

OpenStudy (anonymous):

its actually x^2 + y^2 and I think you saved mi life bro

OpenStudy (anonymous):

i think they are exact lol

OpenStudy (anonymous):

bleh nvm no they're not

OpenStudy (anonymous):

\[-(x^2+y^2)dx+(y^3-2xy )dy=\] My= -2y Nx=-2y yes

OpenStudy (anonymous):

thanks I can take it from there, but I'll be back lol

OpenStudy (anonymous):

I have differential test next week , I can practice by helping

OpenStudy (anonymous):

k

OpenStudy (anonymous):

he so i messed up, it actually is x + y, stuck again

OpenStudy (anonymous):

mebbe i have to find an integrating factor to make it exact?

OpenStudy (anonymous):

ok so I looked at this problem some and I feel I am on the cusp of a breakthrough. I can manipulate this algebraically to make it look like the attached picture. I think I can use that method that uses y/x and substitution. Someone please help.

OpenStudy (anonymous):

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