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Find all zeros of the polynomial function: P(x)=2x^4-10x^3+23x^2-24x+9
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So far I got the list of possible zeros: +/- 1, 1/2,3,3/2,9,9/2 I found 1 works so I did (x-1)(2x^3-8x^2+15x-9)
then [2x^2(x-4)+3(5x-3)]
so do u want the rational or irrational roots?
i found that only 1 works for the rational roots
both i'm assuming
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for all the possibilities, only 1 works
i found it, they are on my bag........
some are on my pocket
in the back of the textbook it states (3/2)+(3/2)i and (3/2)-(3/2)i work, but I don't know to get that
flutter!
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this factors to (x-1)^2(2x^2 - 6x +9) so has a double root of x=1 and two complex roots
complex roots are 6 +- sqrt(36 - 4*2*9 / 4 3/2 + 3i/2 , 3/2 - 3i/2
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