How do I solve this system and graph it? y= x y - 5x = 0
Substitute y with x.. and then solve.
Is y = -5x + 0 ?
Oh wait, you know what... I know exactly what to do... okay, the y-intercept is 0, and the slope of the line is positive 5
Ok
:) Hope that helped
So is it y= 5x + 0 ? Im probably wrong lol
yep
you never need to write "+ 0"
y = 5x then?
well yeah, but it might help her to realize what the y-int is.
The use of the zero is optional
and if y=x.. then the slope of that line is 1 and the y-int is 0 again. tw
they are two lines that intersect at (0,0) sub x in for y in eqn.2 and you have -4x=0 x=0 and since x=y we have y=0 also
the only difference in these two lines are the slope, their y-int's are both 0, so they start from the origin, one with slope 1 the other with slope 5
Here you have two line. The solution to a system of two lines is their point of intersection (if one exists). So you have y=x y=5x we set the two equations to equal each other to find their point of intersection. So, x=5x this is true only when x=0. so our solution is the point (0,0). To graph, start at the origin and draw two line, one of slope=1 and the other of slope=5.
Ok so thats one slope right?
we have two lines here, each of which has it's own slope.
Ok
Join our real-time social learning platform and learn together with your friends!