Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

How do I solve this system and graph it? y= x y - 5x = 0

OpenStudy (anonymous):

Substitute y with x.. and then solve.

OpenStudy (anonymous):

Is y = -5x + 0 ?

OpenStudy (anonymous):

Oh wait, you know what... I know exactly what to do... okay, the y-intercept is 0, and the slope of the line is positive 5

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

:) Hope that helped

OpenStudy (anonymous):

So is it y= 5x + 0 ? Im probably wrong lol

OpenStudy (anonymous):

yep

OpenStudy (turingtest):

you never need to write "+ 0"

OpenStudy (anonymous):

y = 5x then?

OpenStudy (anonymous):

well yeah, but it might help her to realize what the y-int is.

OpenStudy (anonymous):

The use of the zero is optional

OpenStudy (anonymous):

and if y=x.. then the slope of that line is 1 and the y-int is 0 again. tw

OpenStudy (turingtest):

they are two lines that intersect at (0,0) sub x in for y in eqn.2 and you have -4x=0 x=0 and since x=y we have y=0 also

OpenStudy (turingtest):

the only difference in these two lines are the slope, their y-int's are both 0, so they start from the origin, one with slope 1 the other with slope 5

OpenStudy (anonymous):

Here you have two line. The solution to a system of two lines is their point of intersection (if one exists). So you have y=x y=5x we set the two equations to equal each other to find their point of intersection. So, x=5x this is true only when x=0. so our solution is the point (0,0). To graph, start at the origin and draw two line, one of slope=1 and the other of slope=5.

OpenStudy (anonymous):

Ok so thats one slope right?

OpenStudy (anonymous):

we have two lines here, each of which has it's own slope.

OpenStudy (anonymous):

Ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!