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Use integration by parts to evaluate the integral. 343x^2cos(7x)dx
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u = 343x^2 dv = cos(7x)dx du = 686xdx v = (sin(7x))/7 ∫udv = uv - ∫vdu = 343x^2*(sin(7x))/7 - ∫(sin(7x))/7*686xdx =49x^2*sin(7x) - ∫sin(7x)*98xdx Then do parts again on the second term, choosing the power function for u...
49x^2(sin7x)+14cos7x-2sin7x
i think
hooray I was right!
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