Question

find the derivative of y= log10 x^2-1/ x

Answer 1

\[y=\log_{10}(\frac{x^2-1}{x})\]?

Answer 2

probably simplest to break this up as
\[\log(x+1)+\log(x-1)-\log(x)\] and differentiate term by term

Answer 3

yes

Answer 4

sorry... my computer is acting really goofy... a lot of lag time..

Answer 5

so you know that
\[\frac{d}{dx}\log_{10}(x)=\frac{1}{x\log(10)}\] and apply this to each term

Answer 6

that last one means natural log of ten. maybe i should write
\[\frac{d}{dx}\log_{10}(x)=\frac{1}{x\ln(10)}\] to make it look like it probably does on the book

Answer 7

so maybe i am being silly. you could write
\[\frac{1}{\ln(10)}(\frac{1}{x+1}+\frac{1}{x-1}-\frac{1}{x})\] or i guess you could write
\[\frac{1}{\ln(10)}\times\frac{x}{x^2-1}\]