how can i solve for x in sqrt of 2x-4 minus sqrt of x-5 = 3

Question

anonymous · Answer

maybe 
$$\sqrt{2x-4}-\sqrt{x-5}=2$$

anonymous · Answer

yeah thats right, but its = 3 not 2

anonymous · Answer

start with 
$$\sqrt{2x-4}=\sqrt{x-5}+3$$ and square both sides

anonymous · Answer

this is going to be a drag because you are going to have to square twice, and also check  your answer. first time  you get 
$$2x-4=x-5+9+6\sqrt{x-5}$$

anonymous · Answer

this gives 
$$x-8=6\sqrt{x-5}$$ and then square again to get 
$$(x-8)^2=36(x-5)$$
$$x^2-16x+64=36x-180$$
$$x^2-52x+244=0$$

anonymous · Answer

then i guess you can solve using the quadratic formula, but the numbers are so annoyingly large it might be easier to complete the square. your choice

anonymous · Answer

thanks