how do you find the formula for Sodium carbonate
i know that its Na2CO3 but how do you get that???
no Na2CO3 is sodium carbonate
for bicarb u need to add an H+ ion NaHC03
yeah thats what i need... im asking how you get it...
Basically, you add CO2 to NaOH
CO2 + 2 NaOH → Na2CO3 + H2O Na2CO3 + CO2 + H2O → 2 NaHCO3
So, by adding more CO2 to NaOH we get sodiumbicarbonate
does that help?
no not rly i entered my answer and t was right. my question is where does the O3 come from?
i understand Sodium is 1+ and carbonate is 2- but i just dont know where the O3 comes from
You have to look at the balanced equation
what do you mean by that?
Carbon is tetravlent(it can form 4 bonds) O- +Na | C=O | O-+Na
ok..
idk im sorry i just rly dont understand chem at all...
its ok:)
here is a link for the structure of NaHCO3 http://en.wikipedia.org/wiki/File:SodiumBicarbonate.png
ok thank you i will chec k it out
ur welcome gud luck
For a start, we know that a sodium atom naturally has 1 electron in its outer shell, right? this outer shell electron will easily be used to fill the shell of the other atoms, thus sodium will be Na^+
The carbonate ion has a carbon atom and three oxygen atoms, carbon has four outer shell electrons and oxygen has two vacancies in its outer orbital, Summing the electrons; 4 from carbon + 3 x(-2) for the oxygen we have - 2 electrons i.e, one shell with two vacancies . Knowing that our species is Sodium Carbonate, all that is left is to do find how many of each sodium ions and and carbonate ions sum to a neutral molecule \[aNa ^{+} + bCO _{3}^{-2} = 0\] the simplest solution is two sodiums and one carbonate, ie \[2Na ^{+}+1xCO _{3}^{-2} = 0\rightarrow Na _{2}CO _{3}\]
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