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OpenStudy (anonymous):
integrate 9dv/81 - v^4
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OpenStudy (anonymous):
\[\int\limits_{}^{}9dv/81 - v^4\]
OpenStudy (anonymous):
is it integral 9/81 -v^4 dv?
OpenStudy (anonymous):
1/9-v^4 dv
1/9v-(v^5)/5+C
OpenStudy (anonymous):
\[\int\limits_{}^{}(9dv)/(81 - v^4)\]
OpenStudy (anonymous):
Oh !
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OpenStudy (anonymous):
it uses tanx
OpenStudy (anonymous):
it is pretty lengthy
OpenStudy (anonymous):
my solutions manual shows \[1/12 \ln|(3+v)/(3-v)| + (1/6) \tan^{-1} (v/3) + C\]
OpenStudy (amistre64):
81-v^4 = (9+v^2)(9-v^2)
= (9+v^2)(3+v)(3-v)
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OpenStudy (amistre64):
id do partial decomps
OpenStudy (amistre64):
\[\frac{9}{(81-v^4)}=\frac{Ax+B}{(9+v^2)}+\frac{C}{(3-v)}\frac{D}{(3+v)}\]
OpenStudy (amistre64):
Av+B that is
OpenStudy (anonymous):
I KNEW IT WAS PARTIAL FRACTIONS!!!!!!
OpenStudy (amistre64):
lol .... they do help
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OpenStudy (anonymous):
yea i was stuck on how i go about breaking it down to irreducible factors though
OpenStudy (anonymous):
but i knew it was somewhere with partial fractions thanks
OpenStudy (amistre64):
\[\frac{9}{(81-v^4)}=\frac{Av+B}{(9+v^2)}+\frac{C}{(3-v)}+\frac{D}{(3+v)}\]
\[\small 9=Av+B(3-v)(3+v)+C(3+v)(9+v^2)+D(3-v)(9+v^2)\]
OpenStudy (anonymous):
for future reference, how do i place numbers over other numbers in the equations tab when i ask a question? Instead of using the / sign.
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