Question

limits question, please help! equation will be be posted in a few minutes on the equation editor.

Answer 1

Ok

Answer 2

\[\lim_{h \rightarrow 0} \left[ (2+h)^3-8 \right]\div h\]

Answer 3

have you learned l'hospitals rule yet?

Answer 4

no

Answer 5

whats that?

Answer 6

I don't see the limit problem

Answer 7

thats not hopitals rule...

Answer 8

its right under your first reply.

Answer 9

basically l'hospitals rule says that if the limit is indeterminant and is in a form F(x)/G(x) then the limit can be found by taking F'(x)/G'(x)

Answer 10

you need to cube it out:

(2+h)(2+h)(2+h) = h^3 + 6h^2 + 12h +8

So now when we subtract 8, we are left with all terms that have an h attached to them.

So cancel an h from every term and get rid of the h in the denominator and then plug in h=0 to get a final answer of:

12

Answer 11

thank you! :)