How many GRAMS of copper(2) iodide are present in 4.95 moles of this compound?

How many MOLES of copper(2) iodide are present in 4.73 grams of this compound?

Question

How many GRAMS of copper(2) iodide are present in 4.95 moles of this compound?

How many MOLES of copper(2) iodide are present in 4.73 grams of this compound?

anonymous · Answer

Would this not be better asked in Chemistry? They're used to dealing with this sort of stuff...
Anyway $$n \times RMM = m$$
RMM of Cu(II)I2 is I think: 63.15+126.9+126.9= 316.95
Although copper 2 iodide isn't stable - but anyway!
4.95 x 316.95 =  1,568.9025g (or 1.57kg)
Same again but backwards: n = m/RMM
n = 4.73/316.95
n = 0.01492