Question

is there anyone here?

Answer 1

for ???

Answer 2

whats up

Answer 3

i would really really appreciate it if you would help me out with a derivative problem :)

Answer 4

the problem is: g(x) = 1/x+2 ...i need to find derivative using def of limit

Answer 5

It's a pain to write out limit definitions of derivatives on this site, so people don't want to bother trying. Neither do I, frankly.

Answer 6

if I had a pen and paper it would be a lot easier...

Answer 7

if you wouldnt mind i just need help with finding a common denominator within that problem...i can try to figure out the rest myself..

Answer 8

Definition of the derivative is \[\lim_{h \rightarrow 0} \frac{f(x+h) - f(x)}{h}\] So find f(x+h) and then simplify. So \[\lim_{h \rightarrow 0} \frac{\frac{1}{x+h+2} - (\frac{1}{x+2})}{h}\] Now you have to find a common denominator in the numerator so it will look like \[\lim_{h \rightarrow 0} \frac{\frac{(x+2) - (x + h +2)}{(x+h+2)(x+2)}}{h}\] Now we must divide by h so \[\lim_{h \rightarrow 0} \frac{(x+2)-(x+h+2)}{h(x+h+2)(x+2)}\] Can you get it from here?

Answer 9

limit as h goes to zero of