Question

∫cscπxcotπx dx

Answer 1

your missing a -pi

Answer 2

huh?

Answer 3

if we simply try to evaluate where this comes from:

d/dx csc(pi x); we get

-pi csc(pi x) cot(pi x)

and we could simply revert it back again

Answer 4

so you are missing a -pi; borrow one from -pi/-pi

Answer 5

\[\frac{-1}{pi}\int-pi\ csc(pix)cot(pix)dx\]

\[\frac{-csc(pix)}{pi}\]

Answer 6

+C lol

Answer 7

if it doesnt make sense, youll have to just let me know

Answer 8

got it. i used πx = u and did substitution. i just didn't see that you were doing that

Answer 9

yeah, thats the "proper" way to practice a u-sub. :) good job