Question

evaluate integral e^square root x / square root x dx Use substitution rule

Answer 1

yes use
\[u=\sqrt{x}\]
\[du=\frac{1}{2\sqrt{x}}dx\] so
\[2du=\frac{dx}{\sqrt{x}}\] and your integral becomes
\[2\int e^u du\]

Answer 2

the anti derivative of
\[e^u\] is
\[e^u\] so you get
\[2e^u = 2e^{\sqrt{x}}\] and don't forget the stupid " Plus C" at the end

Answer 3

thx yea i be forgetting that C