differentiate the function
y=x^(-2/5)

wouldn't that be (-2/5)/(x^2/5)?

Question

differentiate the function
y=x^(-2/5)

wouldn't that be (-2/5)/(x^2/5)?

anonymous · Answer

y=-2/5x^-3/5

anonymous · Answer

wait

anonymous · Answer

read the bottom its -2/5x^-7/5

anonymous · Answer

multiply the 1 in front of the x by the exponent to get -2/5 then you have the x raised to a power and need to subtract 1. so (-2/5)-(5/5) gives -7/5

anonymous · Answer

oh yeah, you are right thanks my friend!

anonymous · Answer

glad to help :)

anonymous · Answer

but one question the power on the denominator can be negative?

anonymous · Answer

wouldnt one flip it to make it positive?

anonymous · Answer

well a negative sign on a exponent means the whole term will be in the denominator, so it will be 1/(x^7/5) or 1/$$1/\sqrt[5]{?} x7$$

anonymous · Answer

ignore the question mark in there lol

anonymous · Answer

ok

anonymous · Answer

also if you think of x^-1. that is 1/x. but you can write it as x^(-1/1) or x^(1/-1) in fractions they mean the same thing. it doesnt matter in the fraction. just if its in the power or not

anonymous · Answer

what about g(x)=(square root of x) -2