Determine the exact values of the intercepts by using the quadratic formula. Then a calculator to evaluate the expressions that you obtain. y=3x^2-12sqrt3x+36
seems pretty much cut and dry
which part of the instructions is giving you troubles?
I am just learning this the quad formula how do i determine a,b,c
a b and c never change; they are pretty well established as the general formula: ax^2 +bx + x in this case: a = 3 b = -12 sqrt(3) c = 36
i typoed my formula :) ax^2 + bx + c
we can simplfy these as well and still get the same answer by dividing off a 3 from them
a = 3 b = -12 sqrt(3) c = 36 a = 1 b = -4 sqrt(3) c = 12
do i go 1x^2+-4sqrt3+12
not if you are trying to actuall use the quadratic formula itself.
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
ok then how do i do this
plug in the values for a b and c into that formula and math away on it
ok
just to give you something to go by for reference: \[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[\frac{-(-4\sqrt{3})\pm\sqrt{(-4\sqrt{3})^2-4(1)(12)}}{2(1)}\]
whatdo i do after this point
"Determine the exact values of the intercepts by using the quadratic formula. Then a calculator to evaluate the expressions that you obtain." That is where the math part come into the picture. all that adding, subtracting, multiplying and dividing amongst the numbers; and simplifying to get to a suitable answer .
do i take the -(-4sqrt3)and do something with this at the begining?
id make it positive and let it sit there till i did the messier part
ok
hunh ... that messier part goes to zero and youre left with 4sqrt(3)/2; which reduce to 2sqrt(3)
ok
thank for your patience
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