Question

Pls give steps. Most probably to be solved using simultaneous linear equations (i.e. pair of linear equations in two variables)

Father's age is 3 times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

Father's age

Answer 1

let the sum of ages of children =x
fathers age =y

Fathers age is 3 times the sum of ages of his two chidren:
y=3x

After 5 years his age will be twice the sum of ages of two children
y+5=2(x+5)

now solve

Answer 2

@lalaly
substituting y = 3x

3x + 5 = 2x + 10
3x - 2x = 10 - 5
x = 5

so y = 3x = 3*5 = 15

A father of 15 years age !!!!! I doubt it....☺

Answer 3

I am getting answer as 45 years..

Answer 4

how did u do it?

Answer 5

Let age of one child be x years
and age of second child be y years
then father's age will be 3(x + y) years i.e 3x + 3y

After 5 years
first child is x+5 years
second child y+5 years
father's age will be 3x + 3y + 5

ATQ,

3x + 3y + 5 = 2(x+5 + y+5)
3x + 3y + 5 = 2x + 2y + 20
x + y = 15

so fathers age i.e 3(x+y) = 3(15) = 45

Correct??????

Answer 6

yeh ur right my bad=)

Answer 7

No problem. We all go zonkers sometimes....☺☻

I was not sure that is why I posted it here......

Answer 8

lol goodjob;)

Answer 9

Still, thanks for trying.

Can u look-up my other question on pair of linear equations pls...

Answer 10

Sure:D