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solve the seperable equation: dy/dx= (sec^2)y/1+x^2 im not sure how to reach the final answer
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cos^2(y)dy=(1+x^2)dx 1/2+cos(2y)/4=x+x^3/3 +c
thank you!
it says the answer is 2y + sin(2y) = 4 arctan x +C
dy/dx= (sec^2)y/1+x^2 dy/sec^2)y= (1+x^2)dx (cos y)^2 dy=(1+x^2)dx integrating both,sides 2y + sin(2y) = 4 arctan x +C
thank you very much!
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yw
sorry I read question wrong cos^2(y)dy=(1/1+x^2)dx y/2+sin(2y)/4=aractan(x)+C 2y+sin(2y)=arctan(x)+C
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