Question

maybe?

Prove by Contraposition. Let x and y be real numbers. If [x+y >= 2], the [x>=1 or y>=1].

If -[x>=1 or y>=1], then -[x+y >= 2].

If x < 1 and y < 1, then x+y < 2.

Let m be the limit of f(x)=x as x approaches 1 from the left; and let n be the limit of f(y)=y as y approaches 1 from the left. Then the limit of (m+n), as x and y approach 1, approaches 2 from the left.