Question

For the Integral (1/X^p) dx from 0 to 1, find the values of p for which the integral converges ?

Answer 1

are you sure about the boundaries ?

Answer 2

p not 1

Answer 3

i mean p not equal to 1

Answer 4

p is not =1

Answer 5

Yes :(

Answer 6

Why the frown? That's the answer.
\[p \neq1\]

Answer 7

it says find the value of p ?

Answer 8

values of p .. so for p!= 1 converge

Answer 9

how do u prove it

Answer 10

the question wants all values of p that don't converge for that function
\[\int\limits\limits_{0}^{1}1/x^pd=x^(1-p)/(1-p)\] evaluated from 0 to 1
so as long as p isn't 1 you don't get a zero on the denominator, hence the integral is finite (converges)