prove by induction that 7^n-4^n-3^n is divisible by 12, when n is a member of positive integers
you mean when n > 1 ?
when n>0
so do u get it? I really don't know how to do this
ok anyway .. check for n = 1 7^1 - 4^2 - 3^2 = 0 divisible by 12 check for n = 2 : 7^2 - 4^2 - 3^2 = 24 which is divisible by 12 now assume for n=k that (7^k - 4^k - 3^k) / 12 divisible so : no lets check for n+1 : (7^(k+1) - 4^(k+1) - 3^(k+1)) / 12 7*7k/12 -4*4^k/12 - 3*3^k/12 (3+4)*7^k/12 - 4*4^k/12 - 3*3^k/12 3*7^k/12 + 4*7^k/12 - 4*4^k/12 - 3*3^k/12 (7^k - 3^k) /4 + (7^k - 4^k)/3 now for each we have to check that they are divisible (7^k - 3^k)/4 k = 1 true k = 2 true assume k=t divisible (7^t - 3^t)/ 4 k= t+ 1 (7*7^t - 3*3^t )/4 (3*7t + 4*7t - 3*3^t) / 4 7^t + 3*(7^t - 3^t)/4 <- divisible by assumption do the same with : (7^k - 4^k)/3
hope you are still here and sorry that it took me forever
thank you so much
you are welcome in fact it was really challenging, almost gave up im happy to find such questions
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