Question

integrate 4/(x-6)^3 from 6 to 8

Answer 1

it is improper integral night i see

Answer 2

yes it is!

Answer 3

this one doesn't converge either

Answer 4

find the anti derivative, it is
\[\frac{-2}{(x-6)^2}\]

Answer 5

now replacing x by 8 is no problem, you just get a number, namely
\[-\frac{1}{2}\]

Answer 6

but if you try to take the limit
\[\lim_{r\rightarrow 6^+}-\frac{2}{(r-6)^2}\] you get minus infinity, so integral does not exist