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(5x^(2)-6)^(1/4)=x
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25x^4th+36(1/4)=x 6 1/4x+9=x 5 1/4x=-9 x=9 divided by 5 1/4
\[(5x^2-6)^{\frac{1}{4}}=x\] \[(5x^2-6)=x^4\] \[x^4-5x^2-6=0\] \[(x^2-6)(x^2+1)=0\] \[x^2-6=0\] \[x=\pm\sqrt{6}\] \[x^2+1=0\] has no real solution
oops i made a mistake hold on
The solution is √2 and √3
\[5x^2-6=x^4\] \[x^4-5x^2+6=0\] \[(x^2-2)(x^2-3)=0\] \[x^2-2=0\] \[x^2=2\] \[x=\pm\sqrt{2}\] \[x^2-3=0\] \[x^2=3\] \[x=\pm\sqrt{3}\]
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this line \[x^4-5x^2-6=0\] was a mistake on my part. it should have been \[x^4-5x^2+6=0\] sorry about that
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