Question

Find a quadratic equation with the two given numbers as solutions:


2 and -5

Answer 1

x^2 +3x -10

Answer 2

You can go backwords:

(x-2)(x+5) = x^2 +3x -10

and to check the answer, you can use the quadratic equation:

\[( -b \pm \sqrt{b^2 - 4ac} ) /2z\]

Which gives us

\[(-3 \pm \sqrt{(-3)^2 - (4)(1)(-10)} ) / 2a\]

Answer 3

\[-6 + 3i \sqrt{5}\] and \[-6 - 3i \sqrt{5}\]

Answer 4

droid, the solution isn't complex....

Answer 5

different question
sorry

Answer 6

Which results in

(-3 +- sqrt { 9 +40 } ) / 2

So we have

(-3 +- sqrt {49 }) / 2

which gives us

(-3 +- 7) / 2

And in case 1 we have:

x = (-3 + 7)/ 2
x = 4 / 2 = 2

And in case 2 we have:

x = (-3 - 7) / 2
x = -10 / 2 = -5

And so we see that our equation holds.