Question

I need to find the x intercept. Help with steps?
g(x)=3x^3+12x^2+21x+17

Answer 1

put g(x) = 0

Answer 2

yeah, i did that part. But i'm confused just a bit. i got -17=3x(x^2+4x+7). I think I'm having a terrible brain fart

Answer 3

g(x)=0 at:\[x=\frac{1}{3} \left(-4-5 \left(\frac{2}{-29+3 \sqrt{149}}\right)^{1/3}+\left(\frac{1}{2} \left(-29+3 \sqrt{149}\right)\right)^{1/3}\right) \]

Answer 4

Thats what wolfram alpha gave me, but I'm not really sure what that means or how to get that started

Answer 5

x = -1.87984
Plot attached.

Answer 6

I'm just not sure how to show my work for this...

Answer 7

Are you looking for exact solutions?! This would be too hard to find. But you still can find approximate roots using some numerical methods like Newton's.

Answer 8

I'm not really sure to be honest. The original problem was f(x)=x^3-2x^2+3x and g(x)=3f(x+2)-1 List the transformations of f(x) to g(x) and obtain an algebraic representation of g(x)
I got the transformations and g(x)=3x^3+12x^2+21x+17 i think that is right
Then it asks for the x and y intercepts of g(x)

Answer 9

I used Mathematica 8 Home Edition to solve g(x)=0. There is only one real solution and g(x) does not seem to be factorable.

Answer 10

I know there is only 1 solution, I'm just not really sure how to get there. I'm only in precalc so my mathematical knowledge isn't that intense