Question

Find the derivative of the given function 2+ sqrt (x) divided by x^2..... we haven't learned quotient rule yet...

*answer is - (8+3sqrt(x) divided by (2x^3))

Answer 1

\[2+\sqrt{x}\div x^2\]

Answer 2

[2+sqrt(x)]/x^2 = (2/x^2) + [sqrt(x)/x^2]
= 2x^-2 + x^(-3/2)
Use simple differentiation
d/dx ( 2x^-2) = -4x^-3 = -4/(x^3)

d/dx (x^-3/2) = (-3/2)*[x^(-5/2)]

thus adding them you get, -4/(x^3) + (-3/2)*[x^(-5/2)]
= -4/(x^3) - [3/(2*sqrt(x^5)]
Using Least Common Multiple,
you get (-8+3sqrt(x))/(2x^3)

Lemme know if you didnt understand..i'll write it on a paper.

Answer 3

yes could you please write it on paper