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Mathematics 21 Online
OpenStudy (anonymous):

Chain rule! f(x) = sin (sqrt[x]) + sqrt[sin x]

OpenStudy (anonymous):

f(x) = \[\sin \sqrt{x}\] + \[\sqrt{\sin }\]

OpenStudy (across):

Do you know what the chain rule is?

OpenStudy (anonymous):

Hi across, Yes I do and that's what I've been using. The problem is that I'm getting the incorrect answer EVERY TIME. It probably has to do with the sqrt ( [...]^1/2 ) and it being incorrectly used in the equation. I've got about 10 problems left on my homework, but I don't want to move on until I get the right answer (it's odd answer in back of book, so no credit).

OpenStudy (across):

Notice that this function can be rewritten as\[f(x)=g(h(x))+h(g(x)),\]where\[g(x)=sin(x)\]and\[h(x)=\sqrt{x}.\]I hope that makes you see the application clearer.

OpenStudy (anonymous):

Woah! Give me one second to process that. That looks like it may be what I've been looking for!

OpenStudy (anonymous):

How in the heck did you get this formula? I read the section last night and didn't see this anywhere...

OpenStudy (across):

You can come up with it by simple observation... and years upon years of math. -.- If you have any question, let me know.

OpenStudy (anonymous):

Will do. Thanks a bunch, across!

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