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The point P = (-3, 1, -1) is on a line, L, that is parallel to v = <2,4,-3>. Determine another point on L.
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just add 2 toghter
L is parallel to V if its direction vector is equal?
teh vector points to a position as well as a direction; so if you add it to the point; or even subtract it; or any scalar of it; you get a new point on the line
By L and v being parallel; v is the vector for the line
vector arent stationary, they move; just attach it to the point and count
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(-3, 1, -1) <2,4,-3> --------- -1,5,-4 is a point on the line
in fact the line is comprised as: x=-3+2t y= 1+4t z=-1-3t
Ah yea ok, since vectors are parallel if they have a scalar multiple.
yep :)
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