Question

sqrt{36-4x ^{2}} what is the domain and how do you write it in interval?

Answer 1

\[\sqrt{36-4x^2}\] right? this means
\[36-4x^2\geq0\]
\[9-x^2\geq 0\]
now
\[y=9-x^2\] is a parabola that faces down, so it will be negative between the zeros and positive outside them. your answer is
\[-3\leq x\leq 3\] or
\[[-3,3]\]

Answer 2

Thanks Satalite73!!