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Mathematics 11 Online
OpenStudy (anonymous):

Estimate the volume of material in a cylindrical shell with height 30 in., radius 2 in., and shell thickness 0.5 in. im suppose to use linear approximation i think.

OpenStudy (anonymous):

pi r^2 *h. use the radius minus the shell thickness. (if it has a bottom with the same thickness subtract it from there as well. so, either pi(1.5^2)*30 or pi(1.5^2)*25.5

OpenStudy (anonymous):

if theres a top subtract another .5 from the height.

OpenStudy (anonymous):

so i got pi(4)30 - (pi30(1.5^2)) but it is saying that is wrong

OpenStudy (anonymous):

pi (4?) 1.5^2 does not equal 4.

OpenStudy (anonymous):

2^2

OpenStudy (anonymous):

you have to subtract the shell thickness from the radius.

OpenStudy (anonymous):

read my complete first answer and you will see .

OpenStudy (anonymous):

ya i did but wouldent the total volume be = to pi(4)30 then you take that - the other part so it would be pi30(1.5^2)

OpenStudy (anonymous):

yup. and if it has a bottom and/or a top, you have to subtract the shell thickness from the height as well.

OpenStudy (anonymous):

so pi(2^2)*30 - pi (1.5^2)*29

OpenStudy (anonymous):

hummm its not talking it it makes sense to me though

OpenStudy (anonymous):

its saying find dV

OpenStudy (anonymous):

that gives you the volume of the total minus volume of inside.

OpenStudy (anonymous):

does it want whats in the shell or inside the container? you have 2 answers then. either the pi (1.5^2)*29 is your answer or the pi(2^2)*30 - pi (1.5^2)*29 is your answer

OpenStudy (anonymous):

idk there might be an error with the key because this is what i was getting. the only problem i see is the fact that it says to estimate the volume and that is giving us the exact volume

OpenStudy (anonymous):

perhaps god luck then. sorry the book doesnt like the exact answer.

OpenStudy (anonymous):

ya anyway ty

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