Estimate the volume of material in a cylindrical shell with height 30 in., radius 2 in., and shell thickness 0.5 in. im suppose to use linear approximation i think.
pi r^2 *h. use the radius minus the shell thickness. (if it has a bottom with the same thickness subtract it from there as well. so, either pi(1.5^2)*30 or pi(1.5^2)*25.5
if theres a top subtract another .5 from the height.
so i got pi(4)30 - (pi30(1.5^2)) but it is saying that is wrong
pi (4?) 1.5^2 does not equal 4.
2^2
you have to subtract the shell thickness from the radius.
read my complete first answer and you will see .
ya i did but wouldent the total volume be = to pi(4)30 then you take that - the other part so it would be pi30(1.5^2)
yup. and if it has a bottom and/or a top, you have to subtract the shell thickness from the height as well.
so pi(2^2)*30 - pi (1.5^2)*29
hummm its not talking it it makes sense to me though
its saying find dV
that gives you the volume of the total minus volume of inside.
does it want whats in the shell or inside the container? you have 2 answers then. either the pi (1.5^2)*29 is your answer or the pi(2^2)*30 - pi (1.5^2)*29 is your answer
idk there might be an error with the key because this is what i was getting. the only problem i see is the fact that it says to estimate the volume and that is giving us the exact volume
perhaps god luck then. sorry the book doesnt like the exact answer.
ya anyway ty
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