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Mathematics 20 Online
OpenStudy (anonymous):

need help on the attachment

OpenStudy (anonymous):

OpenStudy (across):

Derivative of\[f(x)=2\ln\sqrt{\frac{2x^2-1}{2x^2+1}}?\]

OpenStudy (across):

By the way, how is UT doing?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

how do you know I go to UT??

OpenStudy (across):

Don't send screenshots of your desktop. ;p

OpenStudy (across):

Well, you have to perform the chain rule a few times as well as the quotient rule.

OpenStudy (across):

It's a nasty differential.

OpenStudy (anonymous):

Oh, lol, well UT is great its just to hot down here.

OpenStudy (across):

\[f'(x)=2\frac{1}{\sqrt{\frac{2x^2-1}{2x^2+1}}}\frac{1}{2\sqrt{\frac{2x^2-1}{2x^2+1}}}\frac{(2x^2+1)4x-(2x^2-1)4x}{(2x^2+1)^2}\]

OpenStudy (across):

... then you can try simplifying that.

OpenStudy (anonymous):

well you can take out a 4x from each term on the numerator

OpenStudy (anonymous):

the answer would just be 4x/(2x^(2)+1)^2

OpenStudy (anonymous):

well actually the numerator is 0, is that right??

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