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Derivative of\[f(x)=2\ln\sqrt{\frac{2x^2-1}{2x^2+1}}?\]
By the way, how is UT doing?
yes
how do you know I go to UT??
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Don't send screenshots of your desktop. ;p
Well, you have to perform the chain rule a few times as well as the quotient rule.
It's a nasty differential.
Oh, lol, well UT is great its just to hot down here.
\[f'(x)=2\frac{1}{\sqrt{\frac{2x^2-1}{2x^2+1}}}\frac{1}{2\sqrt{\frac{2x^2-1}{2x^2+1}}}\frac{(2x^2+1)4x-(2x^2-1)4x}{(2x^2+1)^2}\]
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... then you can try simplifying that.
well you can take out a 4x from each term on the numerator
the answer would just be 4x/(2x^(2)+1)^2
well actually the numerator is 0, is that right??
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