Question

Evaluate the integral of sinx(1+cos³x) dx from (0, π)

Answer 1

let u= cos(x)

Answer 2

du= -sin(x) dx

sin(x) dx= -du

Answer 3

Change limits

when x=pi, u= -1

when x=0, u=1

Answer 4

\[= \int\limits_{1}^{-1} -(1+u^3) du = \int\limits_{-1}^{1} (1+u^3) du \]

Answer 5

you can do the rest, its easy.

Answer 6

=2

Answer 7

thank you!

Answer 8

wait is the integral of 1 = u?