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Mathematics 15 Online
OpenStudy (anonymous):

Find the d/dx of : f(x)=(e^x)/((ex+2)(x+3))

OpenStudy (anonymous):

sorry the second bit is e^x as well not ex

OpenStudy (anonymous):

ok...now I got it.

OpenStudy (anonymous):

use d/dx [u/v]=(vu'-uv')/v^2

OpenStudy (anonymous):

yes I did that and I still couldn't get it. My last attempt I got an answer of e^x(1-2x-3e^x) / ((e^x+2)(x+3))

OpenStudy (anonymous):

did you get this from the first step? \[(e^x(e^x+2)(x+3)-e^x(e^x(x+3)+e^x+2))/((e^x+2)(x+3))^2\]

OpenStudy (anonymous):

...made a mistake. Took the derivative of x+3 as x. Thanks for the help!

OpenStudy (anonymous):

you are welcome.

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