Question

need help on the attachment

Answer 1

\[y'=x^{-x^2} (-x-2 x \text{Log}[x]) \]\[\int\limits x^{-x^2} (-x-2 x \text{Log}[x])dx=x^{-x^2} \]

Answer 2

\[-x^{1-x^2} (1+2 \text{Log}[x]) \]is the derivative simplified.

Answer 3

we haven't talk about integrals and that not one of the answer, here are the answers choices

Answer 4

I forgot put one more answer which was y'(x)=-xy(2lnx+1)

Answer 5

Oops I meant one more answer choice

Answer 6

\[y'=x^{-x^2} (-x-2 x \text{Log}[x]) \]Replace the term in front of the left paren with y and then factor out x:\[y'=y (-x-2 x \text{Log}[x]) \]\[y'=x y (-2 \text{Log}[x]-1) \]The above is very close to #5, however there is a sign conflict with the Log term.