Question

7log4^(2x-8)= log4^4x+4

Answer 1

Just checking. Should that 4x+4 at the end be in parentheses?

Answer 2

No it's open.

Answer 3

Is it \[\log 4^{4x+4}\] or \[\log 4^{4x} + 4\]

Answer 4

The first one.

Answer 5

The log identity to use here is \[a \log b = \log b^a\]

Answer 6

You've been looking at this question a while now Marina. Feel free to chime in lol. All help is welcomed

Answer 7

x=6

Answer 8

Thanks to you both. May I ask how you arrived at that answer Marina?

Answer 9

By using the log identity dmancine gave you. In addition, it's very helpful if you will use as many parenthesis as needed to avoid any confusion.

Answer 10

7(2x-8)log4=(4x+4)log4

Answer 11

14x-56=4x+4
10x=60
x=6

Answer 12

Just to get clarification for the future, should the bases be different, do you use the same log identity?

Answer 13

If you really mean the base of the log, then you can use the identity\[\log _{a} b = (\log b) / (\log a)\]

Answer 14

Ok I figured that. Just wanted to make sure.

Answer 15

I am glad that both of us were helful :-)