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OpenStudy (anonymous):
log3(xy)^3-log3xy= 3log3????
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OpenStudy (across):
I'm not sure I understand the equation. Is it\[\log_{3}{(xy)^3}-\log_{3}{(xy)}=3\log_{10}{(3)}?\]
OpenStudy (anonymous):
yes
OpenStudy (across):
First of all, do you think we can simplify the left-hand-side? Perhaps using this property\[\log(a)-\log(b)=\log(\frac{a}{b})?\]
OpenStudy (anonymous):
no, the 3log3 was my answer to the question
OpenStudy (across):
Well, the LHS of the expression is a function of x and y whilst the RHS is a constant. How can that be?
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OpenStudy (anonymous):
what is LHS?
OpenStudy (across):
left-hand-side
OpenStudy (anonymous):
left hand side
OpenStudy (anonymous):
I have never seen these problems in my life, I only started Logarithms today.
OpenStudy (across):
\[\log_{3}(xy)^3-\log_{3}(xy)=\log_{3}(x^3y^3)-\log_{3}(xy)=\log_{3}(\frac{x^3y^3}{xy})=?\]
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OpenStudy (anonymous):
log x2 y2?
OpenStudy (anonymous):
base 3
OpenStudy (across):
That's correct.
OpenStudy (anonymous):
and that cam be simplified to 2log3(xy) right??
OpenStudy (across):
Yep:\[\log_{3}{(x^2y^2)}=\log_{3}{(xy)^2}=2\log_{3}{(xy)}.\]
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OpenStudy (across):
It's all about the properties...
OpenStudy (anonymous):
thank you ms MIT
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