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Mathematics 22 Online
OpenStudy (anonymous):

The demand equation for a certain item is. P=11-x/1000 and C(x)=6000 + 6x

OpenStudy (anonymous):

find marginal profit at production level of 1000

OpenStudy (anonymous):

solve for x by putting 1000 as the value of p

OpenStudy (anonymous):

ok yeah i did that i get $3

OpenStudy (anonymous):

is that right?

OpenStudy (anonymous):

how did you get it?

OpenStudy (anonymous):

find marginal profit at production level of 1000

OpenStudy (anonymous):

revenue is price times demand so I solved for that first which is 11-^2/1000

OpenStudy (anonymous):

yeah thats correct then?

OpenStudy (anonymous):

find marginal profit at production level of 1000

OpenStudy (anonymous):

then to find profit is revenue- cost (5x-(1/1000)x^2-6000

OpenStudy (anonymous):

you are correct i did the same

OpenStudy (anonymous):

find marginal profit at production level of 1000

OpenStudy (anonymous):

what did you get though for marginal profit?

OpenStudy (anonymous):

i solved using quadratic equation and got.....2000 or 3000

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