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Find the particular solution of the differential equation )x^2dy)/(y^2-3dx)=(1/2y) satisfying the initial condition y(1)=(4)^(1/2)
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\[\frac{x^2 dy}{y^2-3 dx}=\frac{1}{2y}\] this one?
yes
\[(x^2 2y )dy-(y^2-3 dx)=0 \] Nx= 4 xy My= 2y so obviously not exact
ok
then
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?
You may have to use special integration factor,
like what?
ok nevermind can u help with this one Solve the separable differential equation for u : du/dt =e^(6u+6t) use the following initial condition u(0)=10
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