Question

A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9^2, where h is the height, in meters, from which the launch occurs, at velocity v meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 140 meters high with an initial upward speed of 50meters per second, what will its height be after 3 seconds.

Answer 1

just plug the numbers dude.
140+50(3)-4.9^2

Answer 2

dont be lazy and just get answers from us. try to do it yourself. it will take less time.

Answer 3

SO it would be 24.01 right?

Answer 4

24.01 is just the 4.9^2

Answer 5

well i did that plug in the numbers and that is what i get, i dont understand where im going wrong

Answer 6

you forgot to hit =

Answer 7

you hit 4.9 the hit the ^2 button. but didnt hit =

Answer 8

i ended up with 265.99 is that right now, yes i did forget to hit the equal sign

Answer 9

logic will save you here. it started higher than 24.01 so it cant be it.

Answer 10

yup. 256.99

Answer 11

265.99

Answer 12

when i go to put my answer in it tell me im wrong, do i have to put u or v next to it

Answer 13

m for meters

Answer 14

so it would then look like this 265.99m right

Answer 15

yup.

Answer 16

careless errors are most ppls problems.

Answer 17

nope still wrong answer

Answer 18

265.99 meters is correct. it probably is looking for 266 m or something. its why i hate those programs

Answer 19

the correct answer was 245.9