Question

(2/x+1)-(1/x-2)=-1/2
Show steps if possible thank you(:

Answer 1

lol easy :D
\[2/(x+1) - (1/x-2) = -1/2\]
\[[[2(x-2)] - [1(x+1)]]/[(x+1)(x-2)]\]
\[(2x-4 - x-1) / (x+1)(x-2)\]
\[x-5 / (x+1)(x-2) = -1/2\]
now just convert into quadratic and then solve for x

Answer 2

How do i do that? i'm not very smart when it comes to this type of math!

Answer 3

not doing your work for you. either ask for help (teacher) or learn to use google
http://www.purplemath.com/modules/solvquad.htm

Answer 4

multiply the x+1 and x-2 to the -1/2

Answer 5

tutordiffeq, you have to let them do at least a part or they gain nothing

Answer 6

i didnt give the answer i just showed the way

Answer 7

that is a confusing place to leave them. once she gets away from the fractions, she should be good.

Answer 8

thank you; tutor that's where i get stuck is the fractions; the thing i'm confused on is; the x-5 on top; so i was wondering what to do.

Answer 9

Okay i got x-5/x^2-x-2=-1/2; i'm confused what to do next.!

Answer 10

move the bottom part of the fraction to the other side of the = by multiplication

Answer 11

so multiply -1/2(x^2-x-2)?

Answer 12

yup

Answer 13

Thanks. :)
should the answers be -4,3?

Answer 14

-1/2x^2-1/2x+6=0
use quadratic and you figure it out. no calc. here for me to use.

Answer 15

Thank you so much for your help; i've learned the quadratic formulas and everything; just not problems like this.!

Answer 16

sometimes you have to think what form can you deal with it in and then look at how you can get it there.