Question

(2/x-5)-(4/x+3)=(8/x^2-9)

Answer 1

[2(x+3) -4(x-5)] / (x-5)(x+3) = 8/(x^2-9)

Answer 2

(26-2x)/ (x-5)(x+3) = 8/ [(x-3)(x+3) ]

Answer 3

multiply both sides by (x+3)

Answer 4

(26-2x)/ (x-5) = 8/(x-3)

Answer 5

Cross Multiply

Answer 6

(26-2x)(x-3) = 8(x-5)

Answer 7

-2x^2 -72x - 78 =8x -40

Answer 8

2x^2+80x+38 =0

x^2 +40x +19 =0

Answer 9

You have to solve the last thing by quadratic formula.

Answer 10

hello there is +32x not -72x

Answer 11

elecengineer please correct your calcules !!!

Answer 12

brittany check it there is not right

Answer 13

yes jhonyy9, I also end up with equation x^2-12x+19=0

Answer 14

so than x_1,_2=(12+/-sqrt(144-76))/2 =(12+/-sqrt(68))/2 =6+/-sqrt(17)

Answer 15

\[(\frac{2}{x}-5)-(\frac{4}{x}+3)=(\frac{8}{x^{2}}-9)\]
\[\frac{2}{x}-5-\frac{4}{x}-3=\frac{8}{x^{2}}-9\]
\[\frac{2}{x}-\frac{4}{x}-\frac{8}{x^2}=5+3-9\]
\[-\frac{2}{x}-\frac{8}{x^{2}}=-1\]
\[-2x-8=-x^{2}\]
\[x^{2}-2x-8=0\]

Answer 16

yes jhonyy9, I have the same
http://www.wolframalpha.com/input/?i=2%2F%28x-5%29-4%2F%28x%2B3%29%3D8%2F%28x%5E2-9%29

Answer 17

ok but look it please iant have wrote one newly possibillity

Answer 18

how is it true ?

Answer 19

this will be need dessiding brittany

Answer 20

PArenthesis were put in totaly different way, but I think 1st version is correct

Answer 21

lol britany which is it?

Answer 22

ok IanT but you need continue again till the end - till solutions

Answer 23

It's late at night. She is sleeoing already :-)).
Good night to everybody!

Answer 24

where is this ? because here is morning 10,23

Answer 25

\[(x+2)(x-4)=0\]
\[x+2=0\]
or
\[x-4=0\]

\[x=-2,4\]

Answer 26

yes x_1= -2 and x_2=4

Answer 27

It was late at night in US.