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could somebody please check my answer, log3 9x^4 - log3(3x)^2 =log3 9x^2 =2log3 9x
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\[\large{\log_3{\frac{9x^4}{9x^2}}}\]\[=\large{\log_3}{x^2}=2\log_3x\]
you forgot to cancel out the 9
why book gives the answer 0
oh then the question might be (3x^2)^2?
coz if it was (3x^2)^2 then the answer will be log3 1^2 = 2log3 1 = 0
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log3 9x4 − log3(3x)2 copied and pasted straight from the worksheet
its either thers something wrong with the question, or the aswer given to u is wrong, the only way it can be zero is when (3x^2)^2 but in this case its 2log3 x
thanks sensei
your welcome:D
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