a particle of mass 2kg is acted on by two forces of magnitude 4N and 2N in the direction i + 2j and 2i - j respectively. Calculate the magnitude of the acceleration of the particle
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OpenStudy (anonymous):
Net force in x direction = 8N
OpenStudy (anonymous):
Net force in y direction = 6N
OpenStudy (anonymous):
Magnitude=10 by a^2=b^2+c^2
OpenStudy (jamesj):
So the unit vector in direction i + 2j is v = 1/sqrt(5)(i + 2j)
Find the unit vector for direction (2i-j), call it w, say
Then the total force is 4v + 2w
OpenStudy (anonymous):
a=F/m =10/2 = 5m/s^2
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OpenStudy (jamesj):
@EE: what you've written for the force above is incorrect, because you didn't normalize the direction vectors.
OpenStudy (anonymous):
F = 4(i+2j) + 2(2i-j) = (8i+6j)
OpenStudy (jamesj):
No. Because i + 2j gives the direction. But that vector has magnitude 5.
OpenStudy (anonymous):
Yeah it's probably wrong.
OpenStudy (jamesj):
so you can't just blithely multiply
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OpenStudy (sasogeek):
thanks a lot :)
OpenStudy (jamesj):
(make that: the vector i + 2j has magnitude sqrt(5) )