a particle of mass 2kg is acted on by two forces of magnitude 4N and 2N in the direction i + 2j and 2i - j respectively. Calculate the magnitude of the acceleration of the particle
Net force in x direction = 8N
Net force in y direction = 6N
Magnitude=10 by a^2=b^2+c^2
So the unit vector in direction i + 2j is v = 1/sqrt(5)(i + 2j) Find the unit vector for direction (2i-j), call it w, say Then the total force is 4v + 2w
a=F/m =10/2 = 5m/s^2
@EE: what you've written for the force above is incorrect, because you didn't normalize the direction vectors.
F = 4(i+2j) + 2(2i-j) = (8i+6j)
No. Because i + 2j gives the direction. But that vector has magnitude 5.
Yeah it's probably wrong.
so you can't just blithely multiply
thanks a lot :)
(make that: the vector i + 2j has magnitude sqrt(5) )
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