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solve the equation sqrt(10-x) + x = 8
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Write this as sqrt(10-x) = 8 -x and square both sides
Solve: \[\sqrt{10-x} + x = 8\]
(\[(\sqrt{10-x} - x = 8 )^{2}\] (\[(\sqrt{10-x}) = (8-x)^2 10 - x = 64 - 16x +x^2 10-x = x^2 - 16x +64 10-x=(x-8)^2
thats what i got so far! but i got stuck
Now multiply out the (x-8)^2 and then collect terms to form a quadratic equation
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10-x = x^2 - 16x +64 ??
x=6
x = 6 is one root, yes. Is there another?
oh no that was it. thanks !
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