Question

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Answer 1

take the limit as x goes to zero of the expression, and then define
\[f(0)=\text{ that number}\]

Answer 2

Can you show me the proper way to solve it? I kept getting the wrong answer, maybe I just didn't understand.

Answer 3

ok hold on let me look

Answer 4

add up the fractions to get
\[\frac{4(x-5)-3x+20}{x(x-5)}=\frac{x}{x(x-5)}=\frac{1}{x-5}\] so if x = 0 you get
\[-\frac{1}{5}\]

Answer 5

that is your limit, and that is the answer to what
\[f(0)\] should be

Answer 6

Ahh, I was pretty close! Thank you very much. I appreciate it.