a store mixes Brazilian coffee worth $12 per kg and Venezuelan coffee worth $15 per kg. the mixture is to sell for $14 per kg. Find how much each should be used to make 348 kg mixture.
First, use a weighted average to find the relative amounts of Brazilian (b) and Venezuelan (v) coffee. They will be percents, so b+v=1. 12b + 15v = 14 Once you have those percents, you can use them to find out how much of each is in the 348kg mixture.
x=116 y=232?
Which one is B and which is V?
i think v=116 b=232? can someone verify with me
Well, telling you that those aren't right will kinda' tell you what is right. But, no, those are backwards. Can you see why?
oh yeah my bad I wrote it down the right way. just didnt type it the right way
I'm going to try a slight variation on dmancine's method; let's see... Let b=pounds of Brazilian coffee needed let v==pounds of Venzuaelan coffee needed then the two can be related by total weight: b+v=348 [eqn 1] they can also be reltaed by cost 12b+15v=14(b+v) or -2b+v=0 solving for v (to use substitution) v=2b [eqn 2] Now sub 2b for v in [eqn 1] b+2b=348 3b=348 b=116 Now sub b=116 into [eqn 2] to find v v=2(116)=232 So, b=116, and v=232
|dw:1317505057415:dw|Here's a simple picture to see what's going on with the weighted average. The desired mix is 2/3 of the way from B to V, so you need more V to pull it closer. The relative distances tell you the relative amounts of each to include in the mix (1/3 and 2/3), and which one it's closer to tells you which one needs to be bigger (closer to V, so v is 2/3).
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