Question

find the derivative:
(square rt(2))/(3y^3)

Answer 1

is this
\[\frac{\sqrt{2}}{3y^3}\]?

Answer 2

yes sir thats it! now it says to find the derivative

Answer 3

ok so suppose the square root of two was not there and you wanted
\[\frac{d}{dy}\frac{1}{3y^3}\] could you find that?

Answer 4

i know you make it (3y^3)^-1

Answer 5

or better still how about
\[\frac{d}{dy}\frac{1}{y^3}\]

Answer 6

i would not suggest doing it that way. first let's find
\[\frac{d}{dy}\frac{1}{y^3}\]

Answer 7

for this one you might want to write
\[\frac{1}{y^3}=y^{-3}\] so
\[\frac{d}{dy}\frac{1}{y^3}=\frac{d}{dy}y^{-3}=-3y^{-4}=\frac{-3}{y^4}\]

Answer 8

then the coefficient
\[\frac{\sqrt{2}}{3}\] gets multiplied by the result. so you get
\[\frac{\sqrt{2}}{3}\times \frac{-3}{y^4}\] which you can clean up some

Answer 9

ok ok ok awesome thank you very much

Answer 10

yw.
don't let the constants fool you. take them out side of the derivative and put them in at the end

Answer 11

ok my prof at Texas A&M says to never deal with rational exponents so she says to make them negative and change them back at the end but your way is easier